thai-pascal's law: hydraulic-lift

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"F" exerted on the small piston at the end of the beam. Then fluid will flow through a
valve 'a' toward large cylinders. Pull upwards the end of the beam, and the small
piston will move upwards, valve 'a' will block the fluid reverse. Valve 'b' is open to
let the fluid from the storage tank flow into a small cylinder. When you press the
beam down again, the fluid will flow into the big cylinder again. Repeatly the cycle
move up and down in several times to make fluid level more in the big piston to be able to
lift a weight W higher. To let the weight W dropping down ,just open valve 'c', and
fluid will allowed to flow into the storage tank.

Example 9.4 Hydraulic Lift
The big piston of the oil jack lift the car,and the surface area of it is 100 times of smaller
one. To lift the car mass 1200 kg, how many newtons is the force required to push
at a small piston?

Strategy

Solution

According to Pascal's law;
We give the surface area of the big piston is "A", and the small piston is "a".
Big piston and small piston will occupy same level of the fluid.
Formulae is ;